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8t^2-14t-85=0
a = 8; b = -14; c = -85;
Δ = b2-4ac
Δ = -142-4·8·(-85)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-54}{2*8}=\frac{-40}{16} =-2+1/2 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+54}{2*8}=\frac{68}{16} =4+1/4 $
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